Archive for 八月, 2009

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Challenging problem in Linear Algebra

八月 19, 2009

Let \mathcal{M} = \left\{ \begin{pmatrix} a & -b \\b & a \end{pmatrix} \, | \, a, b, \in \mathbb{R} \right\}.

Solve the following matrix equation X^4 + X^2 + I = 0 where X \in \mathcal{M}.

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Answers to Linear Algebra Concept Check

八月 19, 2009

Let (E) be the following system:

a_{11}x + a_{12}y + a_{13}z = b_1\\a_{21}x + a_{22}y + a_{23}z = b_2 \\a_{31}x + a_{32}y + a_{33}z = b_3

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Mental exercises for my Pure Complex Class (1)

八月 19, 2009

Dear Students,

Please avoid as much calculations as possible. In ideal situation, you should not do any calculation at all.

Problem 1
Let z = 3 + 4i be a complex number.
(a) Find Re(z).
(b) Find Im(z).
(c) Find \overline{z}.
(d) Find |z|^2.
(e) Find Re(1/z).
(f) What is z \overline{z}?
(g) Suppose z = re^{i \theta}, write r in terms of z

Problem 2
(a) Write z = i in the form re^{i \theta}.
(b) Find the two square roots of i and represent the two square roots on the Gaussian Plane.

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Selected Solutions to My Pure Complex Class (1)

八月 19, 2009

Lesson 1:
Page 26
\begin{aligned} \sum_{k = 1}^{n} \cos^2(k \theta) &= \sum_{k = 1}^{n} \frac{ 1 + \cos(2 k \theta) }{2} \\ &= \frac{n}{2} + \frac{1}{2}\sum_{k = 1}^{n} \cos(2 k \theta) \\ &= \frac{n}{2}  + \frac{\sin(n \theta) \cos((n + 1) \theta)}{2\sin(\theta)}, \end{aligned} where the last line follows from part a(ii).

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Solutions to selected problems for my Olympiad Class

八月 19, 2009

Book 1

Page 1
Answer \binom{3}{2} = 3 which can be looked up from the Pascal Triangle.

Page 2
Answer: \binom{4}{2} = 6.

Page 2
Answer: \binom{6}{3} = 20.

Page 4
Answer: \binom{4}{2} = 6 because we have to travel 4 steps in total, and we need only to decide the 2 horizontal steps.

Alternatively, one can count and add along the way to see that the Pascal triangle appears again as the number of paths.

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Concept Check for my Linear Algebra Students

八月 6, 2009

Let (E) be the following system:

a_{11}x + a_{12}y + a_{13}z = b_1\\a_{21}x + a_{22}y + a_{23}z = b_2 \\a_{31}x + a_{32}y + a_{33}z = b_3

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